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Their were 12 people at the party.
With two people (A and B),
there is one handshake
(A with B).
With three people (A, B, and C),
there are three handshakes
(A with B and C; B with C).
With four people (A, B, C, and D),
there are six handshakes
(A with B, C, and D; B with C and D; C with D).
In general, with n+1 people,
the number of handshakes is the
sum of the first n consecutive numbers:
1+2+3+ ... + n.
Since this sum is n(n+1)/2,
we need to solve the equation n(n+1)/2 = 66.
This is the quadratic equation n2+ n -132
= 0. Solving for n, we obtain 11 as the
answer and deduce that there were 12 people at the
party.
Since 66 is a relatively small number,
you can also solve this problem with a hand calculator.
Add 1 + 2 = + 3 = +... etc.
until the total is 66.
The last number that you entered (11) is n. |